Regression2
regression
dyn
Exercise
Ein Streudiagramm von \(x\) und \(y\) ergibt folgende Abbildung:
Wählen Sie das am besten passende Modell aus der Liste aus!
Solution
Categories:
- regression
- dyn
December 15, 2022
Ein Streudiagramm von \(x\) und \(y\) ergibt folgende Abbildung:
Wählen Sie das am besten passende Modell aus der Liste aus!
Categories:
---
exname: regression2
extype: schoice
exsolution: r mchoice2string(d_five_options$is_correct, single = TRUE)
exshuffle: no
categories:
- regression
- dyn
date: '2022-12-15'
slug: Regression2
title: Regression2
---
<!-- based on Karsten Luebke et al. -->
```{r libs, include = FALSE}
library(tidyverse)
library(mosaic)
library(glue)
library(testthat)
library(exams)
```
```{r global-knitr-options, include=FALSE}
knitr::opts_chunk$set(fig.pos = 'H',
fig.asp = 0.618,
fig.width = 7,
fig.cap = "",
fig.path = "",
echo = FALSE,
message = FALSE,
warning = FALSE,
cache = FALSE,
#dpi = 72,
fig.show = "hold")
```
# Exercise
Ein Streudiagramm von $x$ und $y$ ergibt folgende Abbildung:
```{r paramsets, echo=FALSE}
params <- list()
params$n_set <- c(30, 50, 70)
params$n <- sample(params$n_set, 1)
params$xmin_set <- c(-20,-10)
params$xmin <- sample(params$xmin_set,1)
params$xmax_set <- c(10,20)
params$xmax <- sample(params$xmax_set,1)
params$e_set <- seq(1:7)
params$e <- sample(params$e_set, 1)
params$steigung_set <- c(-10, 10)
params$achsenabschnitt_set <- c(-40,+40)
```
```{r build-grid, echo = FALSE}
d <-
expand_grid(achsenabschnitt_set = params$achsenabschnitt_set,
steigung_set = params$steigung_set) %>%
mutate(item = glue("$y = {achsenabschnitt_set} + {steigung_set} \\cdot x + \\epsilon$"))
```
```{r compute-solution, echo = FALSE}
x <- runif(params$n,
min = params$xmin,
max = params$xmax)
# construct four possible answer options (all possibly correct)
d_five_options <-
d %>%
sample_n(size = 4) %>%
# choose a "correct" model:
mutate(is_correct = sample(x = c(TRUE, rep.int(FALSE, times = nrow(.)-1))))
# Add a fifth option, incorrect
d_one_more_incorrect_option <-
tibble(achsenabschnitt_set = 0,
steigung_set = -40) %>%
mutate(item = glue("$y = {achsenabschnitt_set} + {steigung_set} \\cdot x + \\epsilon$"),
is_correct = FALSE)
# Add wrong options to the other four options:
d_five_options <-
d_five_options %>%
bind_rows(d_one_more_incorrect_option)
# draw the "correct" model:
d_correct <-
d_five_options %>%
filter(is_correct == TRUE)
```
```{r plot-scatter}
# this is the "correct" model per definition
yhat <- d_correct$achsenabschnitt_set[1] + d_correct$steigung_set[1] * x
yi <- yhat + rnorm(params$n, sd = sd(yhat)/params$e)
lm_true <- lm(yi ~ x)
expect_equal(length(yhat), length(yi))
gf_point(yi ~ x)
r2 <- round(rsquared(lm_true), 2)
```
Wählen Sie das am besten passende Modell aus der Liste aus!
```{r questionlist, echo = FALSE, results = "asis"}
answerlist(d_five_options$item, markup = "markdown")
```
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# Solution
```{r}
gf_point(yi ~ x) %>%
gf_lm() %>%
gf_vline(xintercept = 0, color = "grey60", linetype = "dashed") %>%
gf_hline(yintercept = 0, color = "grey60", linetype = "dashed") +
annotate(geom = "point",
x = 0,
y = predict(lm_true, newdata = data.frame(x=0)),
color = "red",
alpha = .5,
size = 5) +
labs(caption = glue("Steigung b={round(d_correct$steigung_set[1], 2)}"))
```
```{r solutionlist, echo = FALSE, results = "asis"}
answerlist(ifelse(d_five_options$is_correct, "Richtig", "Falsch"), markup = "markdown")
```
---
Categories:
- regression
- dyn